2x+y-z=3 5x+3y-z=10 求x+y+z=
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2x+y-z=3 5x+3y-z=10 求x+y+z=
2x+y-z=3 5x+3y-z=10 求x+y+z=
2x+y-z=3 5x+3y-z=10 求x+y+z=
在噢\7
我来见见你吧!虽然现在不上学了.
2X+Y-Z=3
4X+2Y-2Z=6
懂吧,两边都乘以2
(5X+3Y-Z)-(4X+2Y-2Z)=10-6=4
简化下就行了
5X+3Y-Z-4X-2Y+2Z=X+Y+Z=4
等于4上面算出来了不懂追问\7
我来见见你吧!虽然现在不上学了.2X+Y-Z=3
4X+2Y-2Z=6
懂吧,两边都乘以2(5X+3Y-Z)-(4X+2Y-2Z)=10-6=4简化下就行了
5X+3Y-Z-4X-2Y+2Z=X+Y+Z=4等于4上面算出来了不懂追问\7
我来见见你吧!虽然现在不上学了.2X+Y-Z=3 4X+2Y-2Z=6懂吧,两边都乘以2(5X+3Y-Z)-(4X+2Y-2Z)=10-6=4简化下就行了5X+3Y-Z-4X-2Y+2Z=X+Y+Z=4等于4上面算出来了不懂追问
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y+3z=23 y-z=5 x+2z=10
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
X=3z X+y+z=12 X+2y-2z=10
2x+z=10 x+y-z=4 3x-y-z=0
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
x+y+2z=5 2x-y-z=4 3x+y-3z=10
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
2x+y-z=3 5x+3y-z=10 求x+y+z=
-2X+3Y+Z=-4-X-5Y-2Z=-13X+Y-Z=10
x+y-z=5,2x+3y+z=10,x-2y-z=20求方程组
x+y-z=5 2x+3y+z=10 x-2y-z=20 速解,
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian