[(x-y)²+(x+y)(x-y)]除以2x
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[(x-y)²+(x+y)(x-y)]除以2x
[(x-y)²+(x+y)(x-y)]除以2x
[(x-y)²+(x+y)(x-y)]除以2x
=(x²+y²-2xy+x²-y²)/2x
=2x(x-y)/2x
=x-y
原式=(x²+y²-2xy+x²-y²)/2x
=2x(x-y)/2x
=x-y
x²-y²-x-y因式分解
49+14x+x²-y²
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已知x²y²+x²+y²=10xy-16 求x,y
x²-4y² x+2y---------- ÷ --------分数线x²+2xy+y² x²+xyx²-4y² x+2y----------÷--------分数线x²+2xy+y² x²+xy(x+2y)(x-2y)x(x+y)=----------------(x+y)(x+y)(x+2y)(x-y)x=------(x+y)这样对了吗?
(x+y)²-(x³+y³)÷(x+y)
计算 ①[x(x²y²-xy)-y(x²-x³y)]÷3x²y
计算:[x(x²y²-xy)-y(x²-x³y)]÷3x²y
[x(x²y²-xy)-y(x²-x³y)]÷3x²y